You can find the empirical/molecular formula by using the percent composition.
This video discusses using experimental data to calculate a .
video from: Noel Pauller
In the video the percent composition is found to be…
Fe = 77.6%
O = 22.4%
This video uses the experimental data to find the empirical formula of FeO.
video from: Noel Pauller
So what if you don’t have experimental data, just the percent composition? Assume you have a 100g sample, which would mean 77.6g of Fe and 22.4g of O.
Do the calculation just like in the second video:
##((77.6g Fe)/1)x((1 mol Fe)/(55.84 g Fe)) = 1.4 mol Fe##
##((22.4g O)/1)x((1 mol O)/(16.00 g O)) = 1.4 mol O##
You can see the ratio of Fe:O is 1:1 meaning the reaction produced FeO with the iron having an oxidation state of +2.
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