Question Description
please be specific and simple make like it a biggner wrote it not a professional We want to play with Fortran a little.Also need an answers.txt to explain what happens.1. Try to change a literal value in a function.2. Write function which checks for pass by reference.3. Try using a mixed datatype expression.4. Create a 4D or 5D array and make sure it works.5. Create a recursive function and record what happens.*. See if you can trick into really doing recursion. PROGRAM count DO 50 i = 1, 10 PRINT *, 'Number', i50 CONTINUE END DIMENSION MYARR (10, 20, 5) MYARR(1, 1, 1) = 5 MYARR(10, 20, 5) = 5000 PRINT *, MYARR(1, 1, 1) SUBROUTINE name (parameters) whatever code RETURN ENDOriginally Fortran square(7) print 7 ----> Could print 49 PROGRAM FUN CALL ADD(4, 5) END SUBROUTINE ADD (X, Y) ANS = X + Y PRINT *, ANS RETURN END[charon] vi myfunfortran.f[charon] g77 myfunfortran.f[charon] ./a.out DO 50 I = 1, 10 DO50I = 1,10 // This is the start of our loop DO50I = 1.10 // This sets var DO50I to be 1.1 DO50I = 1.10 // This sets var DO50I to be 1.1Note that since all space is ignored and variables are implicitlydeclared, this statement sets DO50I without any warnings or errors.There are dangers in allowing implicit variable declarations (like inFortran), such as a typo which creates a whole new variable withoutany warnings or errors (meaning it is still a logic error but thecompiler won't notify the programmer about the typo). SUBROUTINE ADD (X, Y) TMP = X X = Y Y = TEMP RETURN ENDFortran had an Arithmetic IF which was a 3 way IF statement whichselected the appropriate choice based on the test begin less than,equal, or greater than zero. IF (X) s1, s2, s3 IF (X) Y = Y + 10, Y = Y - 1, Y = Y - 1Before long programmers saw that a more conventional Logical IF(with only true/false) would be easier and more useful. IF (X .GT. 0) Y = Y + 10 IF (X .LE. 0) GOTO 100 Y = Y + 10 GOTO 200100 Y = Y - 1200 ...
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