Question Description
Please answer all 8 questions and see the attached files
Resources: Powerpoint lecture material, lecture notes, and the two codes provided.
Note: For Questions 1-5, use the Rayleigh Code. For the remaining questions, use the Mie Code.
Question 1:
Use the Rayleigh Code. Carefully review the input and output parameters. Make a list of these parameters, and name the optical/physical quantities they correspond to.
Question 2:
What is the forward-to-backward scattering ratio of a 5 nm particle?A 20 nm particle?
Question 3:
For equal concentrations, what are the scattering cross-sections of a 5 nm and a 20 nm particle? How many times larger is the scattering cross-section of the 20 than the 5 nm particle?
Question 4:
Construct graphs showing the power-law dependence of scattered intensity (use the average, or pick an angle) dependence on wavelength and particle radius. What are the power-law exponents?How good is the fit, for a wavelength from 350-700 nm and a size parameter from 0-1?
Question 5:
Can you make the scattered intensity of a collection of 5 and 10 nm particles to be the same?What parameter values for each collection of scattering objects permits this?
Question 6:
Next, run the Mie Code and as before, make a list of any extra variables that represent optical parameters not found in the Rayleigh code. What is the physical/optical meaning of these new parameters?
Question 7:
Examine Figures 4-6. Explain these graphs in words. Specifically address why Mu_S is smaller than Mu. For the values in the original code, what is the size parameter in which the anisotropy factor is approximately 0.5? What does this mean for light scattering?Hint: Look at the Jacques paper for basic definitions and examples of the anisotropy factor, g. Similarly, what is the physical meaning of the reduced scattering coefficient?
Question 8:
Code in the expression for Mie Theory scattered light intensity from a sphere found in the class notes. Plot the scattered power spectrum for a size parameter of x=0.1, x=1, and x=3.
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