Read the following instructions in order to complete this discussion, and review the example of how to complete the math required for this assignment:

•On pages 345, 346, and 353 of Elementary and Intermediate Algebra, there are many factoring problems. You will find your assignment in the following table.

8                                                  x2 + 8x + 15                          2a2 + 1 + 3a                               

Your initial post should be 150-250 words in length. Respond to at least two of your classmates’ posts by Day 7 in at least a paragraph. Do you agree with how they used the vocabulary? Do their answers make sense?

Carefully review the Grading Rubric for the criteria that will be used to evaluate your discussion.

Response 1 -Edward Williamson

Factoring

I was assigned the number 36.  This means that from pages 345-346 that I will work problems 72 and 100.

72. –No Image -100a     The first step to factor this binomial completely is to find the GCF or the greatest common factor.

a is present and can be taken from both terms of this binomial and therefore is the GCF.

a ( No Image  – 100)      This step shows where the GCF has been taken out of the binomial and then is multiplied by what is left.

The terms in the parenthesis are the difference of two perfect squares.  This is true because both  No Image  and 100 are perfect squares.

The binomial would then be written as  a( No Image -102) and then factors to

a (10 + a)(10 – a)  which is the final step in factoring this binomial.

*For some reason the first part of this discussion post is copying in a weird way.  I hope that although the terms are a little above the problem that it is clear where they belong.*

100. 3x3y2 – 3x2y2 + 3xy2   The first step to factor this polynomial completely is to find the GCF. 

The GCF is 3xy2 because this can be pulled from each term in this polynomial. 

3xy2(x2 –x +1)  This step shows where the GCF was removed and what is left is in the parenthesis.

Because there are no factors of 1 that add to -1 this is a prime polynomial and this is as far as this polynomial can be factored.

Page 353

84. a2b + 2ab – 15b    The first step to factor this polynomial using the ac method is to identify which terms are equal to a and which are equal to c and then multiply those terms together.

a = 1 and c = -15 and so therefore ac = -15

The factor pairs of -15 that would equal a positive 2 are 5 and -3.

The next step is to change the polynomial from having 3 terms to four terms by replacing the 2ab with 5ab and -3ab.

a2b + 5ab -3ab -15b    This step shows where the polynomial has four terms and can now be factored by grouping.

ab(a + 5) -3b(a + 5)     This step shows Criminalistics,Law,,

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